UFC: Dana White fires back at Jon Jones after demanding release from contract

UFC, Dana White
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There’s nothing like a good old fashion Twitter war between UFC president Dana White and light heavyweight champion Jon Jones. Jones demanded his release after stating that DeontayWwilder is paid vastly more than him, somewhere in the $25-30 million range, while Jones is making less than half of that.

“Don’t be a f—ing liar,” Jones expressed on Friday, via Twitter. “My reputation has already taking enough hits. I don’t need this bulls— Dana. I never asked for [Deontay Wilder] numbers. And how about since [Wilder] is making $30 million, we settle for half of that. Since you said I’m the [greatest of all time] and everything.”

Jones, who is one of the best fighters in the world, believes he deserves more pay and less BS from White, who continues to undervalue him and ignore his requests. Jones wants a heavyweight fight against Francis Ngannou, and while White has stated that Jones continues to ask for a specific amount of money, Jones has denied those claims.

“He can do whatever he wants,” White said Saturday, per ESPN. “He wants to sit out, fight, he can do whatever. He can say whatever he wants publicly. It’s his God-given right in America. He can say whatever he wants. When he’s ready to come back, he can.

“In one of his tweets, he said I tarnished his name. I tarnished you? You’ve done a very good job of tarnishing you.”

One of the significant issues that Jones faces regarding an increase in pay is his legal history and the questionable image he provides for the UFC as a whole. He has been arrested multiple times throughout his career, and at 32 years old, it doesn’t seem White is willing to give him what he wants.

Hypocritically, White continues to coin Jones has the best MMA fighter of all time but refuses to pay him more than some of the lesser-known athletes. White did indicate that being the best does not make you the most valuable in terms of selling, which ultimately plays a significant factor in the overall numbers.

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